UnitCharts

Metric Thread Tensile Stress Area Chart

Tensile stress area for metric coarse and fine threads — the figure you multiply by the bolt strength class to get its load capacity.

Nominal dia. (mm)Coarse pitch (mm)Coarse stress area (mm²)Fine pitch (mm)Fine stress area (mm²)
The stress area is not the shank area — it is the effective cross-section through the threaded portion, calculated as A = π/4 × ((d2 + d3)/2)² where d2 is the pitch diameter and d3 the minor diameter. Bolt tension capacity = stress area × tensile strength, so a M12 class 8.8 bolt carries 84.3 mm² × 800 MPa ≈ 67 kN, not the 113 kN its 12 mm shank would suggest. Source: ISO 898-1 / ISO 724.

Standard: ISO 898-1 / ISO 724  ·  Data checked: 2026-10-14

Frequently asked questions

Why is stress area smaller than the shank area?

Because a bolt almost always fails through the threaded portion, where the cross-section is reduced by the thread itself. Stress area is the effective area through the threads, calculated from the mean of pitch and minor diameter — so it is smaller than the shank and it is the number to use for load.

How do I get the load capacity of a bolt from this?

Multiply the stress area by the bolt's minimum tensile strength. An M12 class 8.8 bolt has a coarse stress area of 84.3 mm2 and a minimum tensile of 800 MPa, so about 67 kN. Use the yield strength and a safety factor instead if you are sizing for a working load.

Why is the fine thread stress area larger?

A finer pitch removes less material, so the minor diameter is bigger and the stress area with it. That is why fine threads are preferred where fatigue or vibration matters — M12 x 1.25 has 92.1 mm2 against 84.3 mm2 for M12 x 1.75.

Can I just use the shank diameter instead?

No, it overstates capacity by roughly 30% because the thread reduces the cross-section. A calculation based on nominal diameter will tell you a joint is safe when it is not — this is exactly the kind of error that shows up as a sheared bolt.